2x^2+3x+4=2x+36

Solution for 2x^2+3x+4=2x+36 equation:

2x^2+3x+4=2x+36

We move all terms to the left:

2x^2+3x+4-(2x+36)=0

We get rid of parentheses

2x^2+3x-2x-36+4=0

We add all the numbers together, and all the variables

2x^2+x-32=0

a = 2; b = 1; c = -32;
Δ = b2-4ac
Δ = 12-4·2·(-32)
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{257}}{2*2}=\frac{-1-\sqrt{257}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{257}}{2*2}=\frac{-1+\sqrt{257}}{4}
$